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h^2+21h-24=0
a = 1; b = 21; c = -24;
Δ = b2-4ac
Δ = 212-4·1·(-24)
Δ = 537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{537}}{2*1}=\frac{-21-\sqrt{537}}{2} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{537}}{2*1}=\frac{-21+\sqrt{537}}{2} $
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